1/4x^2+5=0

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Solution for 1/4x^2+5=0 equation: 



1/4x^2+5=0



Domain of the equation: 4x^2!=0

x^2!=0/4

x^2!=√0

x!=0

x∈R



We multiply all the terms by the denominator


5*4x^2+1=0

Wy multiply elements

20x^2+1=0

a = 20; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·20·1
Δ = -80
Delta is less than zero, so there is no solution for the equation

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